(2x-7)(3x^2+7x+4)=0

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Solution for (2x-7)(3x^2+7x+4)=0 equation: 


Simplifying
(2x + -7)(3x2 + 7x + 4) = 0

Reorder the terms:
(-7 + 2x)(3x2 + 7x + 4) = 0

Reorder the terms:
(-7 + 2x)(4 + 7x + 3x2) = 0

Multiply (-7 + 2x) * (4 + 7x + 3x2)
(-7(4 + 7x + 3x2) + 2x * (4 + 7x + 3x2)) = 0
((4 * -7 + 7x * -7 + 3x2 * -7) + 2x * (4 + 7x + 3x2)) = 0
((-28 + -49x + -21x2) + 2x * (4 + 7x + 3x2)) = 0
(-28 + -49x + -21x2 + (4 * 2x + 7x * 2x + 3x2 * 2x)) = 0
(-28 + -49x + -21x2 + (8x + 14x2 + 6x3)) = 0

Reorder the terms:
(-28 + -49x + 8x + -21x2 + 14x2 + 6x3) = 0

Combine like terms: -49x + 8x = -41x
(-28 + -41x + -21x2 + 14x2 + 6x3) = 0

Combine like terms: -21x2 + 14x2 = -7x2
(-28 + -41x + -7x2 + 6x3) = 0

Solving
-28 + -41x + -7x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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